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Linear Equations Quiz - CBSE Class 10 Mathematics

Free practice quiz: Linear Equations (CBSE Class 10 Mathematics). 12 multiple-choice questions with answers and explanations. Play online, no sign-up needed.

This CBSE Class 10 Mathematics practice quiz has 12 multiple-choice questions on Linear Equations, and 12 of them come with an explanation. Try the 5 sample questions below (tap an option to check yourself), then play the full quiz online. No sign-up needed.

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About this topic

A pair of linear equations in two variables has the form a₁x + b₁y + c₁ = 0 and a₂x + b₂y + c₂ = 0. Its solution is the pair (x, y) satisfying both equations. Solve by substitution, elimination, or graph. The ratios of coefficients tell you in advance how many solutions exist.

Learn the key ideas Beta

What a Solution Means

  • A pair of linear equations in x and y has the general form shown below.
  • A solution is an ordered pair (x, y) that makes BOTH equations true at the same time.
  • Graphically, the solution is the point where the two lines meet.
General pair
\[a_1x + b_1y = c_1,\quad a_2x + b_2y = c_2\]
Solution as a point
\[(x, y) \text{ satisfies both equations}\]

Common mistake: Checking a found pair in only one equation. It must satisfy both equations, otherwise it is not the solution.

Substitution Method

  • Make one variable the subject of one equation, for example y in terms of x.
  • Put this expression into the other equation, solve for one variable, then substitute back.
Step 1: express y
\[y = \frac{c_1 - a_1x}{b_1},\quad b_1 \neq 0\]
Step 2: substitute
\[a_2x + b_2\left(\frac{c_1 - a_1x}{b_1}\right) = c_2\]

Common mistake: Substituting the expression back into the same equation it came from. This gives a true statement but no new information.

Elimination Method

  • Multiply the equations so that one variable has equal or opposite coefficients in both.
  • Add or subtract the equations to remove that variable, solve, then substitute back to find the other.
Opposite coefficients: add
\[(ax + by) + (cx - by) = (a + c)x\]
Equal coefficients: subtract
\[(ax + by) - (cx + by) = (a - c)x\]

Common mistake: Multiplying only the left side of an equation by a number and forgetting to multiply the constant on the right side too.

Number of Solutions by Ratios

  • Compare the coefficient ratios to find whether the lines intersect, coincide or are parallel.
  • Coincident lines give infinitely many solutions. Parallel lines give no solution.
Unique solution (intersecting)
\[\frac{a_1}{a_2} \neq \frac{b_1}{b_2}\]
Infinitely many (coincident)
\[\frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2}\]
No solution (parallel)
\[\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}\]

Common mistake: Trying to find one intersection point for coincident lines. When one equation is a multiple of the other, every point on the line is a solution.

Exam tips

Beta: made with AI and checked by a second AI. A teacher has not reviewed it yet.

Sample questions

  1. The solution of 4x - y = 7 and 2x + y = 1 is:

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    Answer: A. x = 2, y = -3

    Add the two equations: 4x - y + 2x + y = 7 + 1. This gives 6x = 8, so x = 2. Substitute x into 2x + y = 1 gives y = -3.

  2. Solve for x and y: x - 2y = 3 and 3x + y = 5.

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    Answer: A. x = 1, y = 1

    From x - 2y = 3, x = 2y + 3. Substitute in 3x + y = 5 gives y = 1. Then x = 1.

  3. What is the value of x in the equation: 3x + 4y = 10 and x = 2y + 1?

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    Answer: A. x = 3

    Substitute x = 2y + 1 in 3x + 4y = 10 simplifies to y = 1, then x = 3.

  4. Determine the y-value in: x + y = 5 and 2x + 2y = 10.

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    Answer: D. Infinite solutions

    Both equations represent the same line, thus there are infinite solutions.

  5. Solve for x and y: 4x + y = 9 and 3x - y = 3.

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    Answer: A. x = 2, y = 1

    Add equations: (4x + y) + (3x - y) = 12 gives 7x = 12 so x = 2. Substitute to find y = 1.

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More questions in this quiz

Answers and explanations are in the full quiz.

  1. If x + y = 10 and x - y = 2, what are the values of x and y?
  2. Determine the point of intersection for the lines: x + 2y = 8 and 2x + 4y = 16.
  3. Find the value of y for the equations: 5x + y = 11 and 3x - y = 5.
  4. Calculate x for the system: 7x + 3y = 20 and x - y = 0.
  5. The equations x + 2y = 3 and y - x = 1 are given, solve for x.
  6. Find x for x + 3y = 6 and 2x - y = 3.
  7. Calculate the solution for: x + y = 7 and 3x + 2y = 18.

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